Mathematics: What is the general form of the equation of a circle with its center at (-2, 1) and passing through (-4, 1)? x2 + y2 − 4x + 2y + 1 = 0 x2 + y2 + 4x − 2y + 1 = 0 x2 + y2 + 4x − 2y + 9 = 0 x2 − y2 + 2x + y + 1 = 0

What is the general form of the equation of a

Ответ:

raweber

04.01.2022

First use the standard form:
(x-h)^2+(y-k)^2=r^2

(h,k) - the coordiantes of the center

The center is (-2,1).
$(x-(-2))^2+(y-1)^2=r^2 \\
(x+2)^2+(y-1)^2=r^2$

The circle passes through the point (x,y)=(-4,1).
$(-4+2)^2+(1-1)^2=r^2 \\
(-2)^2+0^2=r^2 \\
r^2=4$

The standard form is:
(x+2)^2+(y-1)^2=4