Mathematics: What is the lim as x-- infinity (5e∧-x + 1)^2e^x

What is the lim as x-- infinity (5e∧-x + 1)^2e^x

Ответ:

JayHtx9529

05.01.2022

$\displaystyle\lim_{x\to\infty}(5\e^{-x}+1)^2e^x=\lim_{x\to\infty}\frac{(5e^{-x}+1)^2e^{2x}}{e^x}=\lim_{x\to\infty}\frac{(5+e^x)^2}{e^x}$

Replacing y=e^x

, the limit is equivalent to

$\displaystyle\lim_{y\to\infty}\frac{(5+y)^2}y$

which clearly approaches $\infty$ .

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Ответ:

stodd9503

01.07.2020

Mathematics

164 tickets

Step-by-step explanation:

We can denote number of adult tickets as "y"

Then if number of adult tickets is "y" then number of student tickets can be expressed as (480-y)

We were given Total cost of tickets as ($2892) eqn(1) and the cost of adult ticket is $8 per one, and also Cost student ticket $5 per one

the algebra equation can be expressed as :

8y + 5y= 2892

If we substitute eqn (1) we have

8y + 5(480 - y) = 2892

8a + 2400 - 5y = 2892

2892 - 2400= 8y-5y

492=3y

y = 164

Therefore, the number of adult tickets sold is 164

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What is the lim as x--> infinity (5e∧-x + 1)^2e^x

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