What is the recursive formula for this geometric

Ответ:

diwashkandel6pe02af

11.03.2022

$a_{n+1}$ = - 3 $a_{n}$ with $a_{1}$ = 4

To find the next term in the sequence multiply the previous term by - 3

the common ratio r = $\frac{-108}{36}$ = $\frac{36}{-12}$ = - 3

$a_{n+1}$ = $a_{n}$ × r ← recursive formula

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Jxsolvez

11.03.2022

$a_{n+1}=-3a_{n}$

Step-by-step explanation:

The recursive formula for geometric sequence is given by :-

$a_{n+1}=a_{n}r$ -----(1) , where r = common ratio and n=natural number .

nth term of geometric sequence = $ar^{n-1}$

The given geometric sequence : 4,-12,36,-108...

First term = a_1=a=4

Second term = a_2=ar=-12

Also, $r=\dfrac{ar}{a}=\dfrac{-12}{4}=-3$

∴ r = -3

Put the value of r in (1) , we get the recursive formula for given geometric sequence as

$a_{n+1}=a_{n}(-3)$

i.e. $a_{n+1}=-3a_{n}$

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Jaymiegrimes22

12.04.2023

Here are the examples for

1. a normal line to a line

The corner of a photo frame, or the corner of a note book

2. A normal line to a circle

A circular plate balanced on a scale

3. A normal line to a plane

The pole standing on a plain ground

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