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ellisc7044
13.07.2019 •
Mathematics
What is the solution set to the equation (2x−4)(4x−5)=0
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Ответ:
Step-by-step explanation:
We know that for equation of type
, solutions are
as both points x = a and x = b satisfy the equation (x-a)(x-b)=0
Given : equation (2x−4)(4x−5)=0
To find : Solution set of this equation .
Solution :
On dividing this equation by 2 and 4, we get
On comparing equation
with
, we get ![a=2\,,\,b=\frac{5}{4}](/tpl/images/0084/8951/53aa5.png)
Therefore, solution set is![\left \{ 2,\frac{5}{4} \right \}](/tpl/images/0084/8951/fd279.png)
Ответ:
Option C
Step-by-step explanation:
Let X be a discrete random variable that counts the number of siblings a randomly selected student has. Then the expected value of X is defined as:
Where
is the probability that a randomly selected student has
siblings
With![i = \{0,1, 2, 3, 4, 5\}](/tpl/images/0174/1489/e3f09.png)
So in this case we know that
#of siblings 0 1 2 3 4 5
probability 0.20 0.65 0.08 0.04 0.02 0.01
Therefore:
The answer is the option C.