What is the solution to 3+ 4e^X+1=11? O x = In 2-1
O X=In2+1
O X- x-
e
e+2
OX-
e

x = 1   ,or   x = -7

Obviously, the true answer is not in the options given.

Step-by-step explanation:

x² + 6x - 6 = 10

The above equation can not be factorized, hence the use of Almighty Formula.

x = [-b +- √b² - 4ac] / 2a

Where a = 1, b = 6, c = -6

x = [-6 +- √6² - (4*1*-6)] / 2*1

x = [-6 +- √36 - (-24)] / 2

x = [-6 +- √36 + 24] / 2

x = [-6 +- √60] / 2

x = [-6 +- 7.75] / 2

x = [-6 + 7.75] / 2   ,or   x = [-6 - 7.75] / 2

x = 1.75/2   ,or   x = -13.75/2

x = 0.875   ,or   x = -6.875

Approximately

x = 1   ,or   x = -7

x=In2+1

Step-by-step explanation:

3+4ex+1-3=11-3

0+4ex+1=8

4ex+1=8

 2**n. (That's two to the nth power: 2 to the first, 2 to the second (or two squared), 2 to the third (or two cubed), 2 to the fourth, etc.) 

2**1 = 2 = 2 
2**2 = 2 * 2 = 4 
2**3 = 2 * 2 * 2 = 8 
2**4 = 2 * 2 * 2 * 2 = 16