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08.10.2019 •
Mathematics
What is the solution to the equation below? log64x^2-log6x=2
x=1/2
x=3/2
x=3
x=9
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Ответ:
x>0
We will apply the formulas:
loga(x) - loga(y) = loga(x/y)
and
if loga(x)=b then x = a^b
log6(4x^2)-log6(x)=2
Applying first formula
log6(4x^2/x) = 2
log6(4x) =2
Applying the second formula:
4x = 36
x=9
Ответ:
Step-by-step explanation: