What is the Total number of Outcomes for a family of 3 with having boys and girls?

There are 8 possible outcomes, all equally likely (if we assume each gender is equally likely). Hence the choice is 3/8. We can also think about it in at least one more way: You identified all the possible ways to get 2 boys and one girl.

Option A is correct

Step-by-step explanation:

It is given that LMNO, OPQR, QUTS are parallelograms and L, O, and P are collinear, N, O, and R are collinear., S, Q, and R are collinear, P, Q, and U are collinear.

Thus, ∠M=∠1(Because they are opposite angles of parallelogram LMNO), ∠1=∠2 (as they are vertically opposite angles). Again ∠2=∠3(Because they are opposite angles of parallelogram ROPQ), ∠3=∠4 (as they are vertically opposite angles).

Thus, ∠M=∠1=∠2=∠3=∠4⇒∠M=∠4

Hence proved.

Hence, option A is correct as it has the same conditions used above.