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nini261
31.01.2021 •
Mathematics
Where are the zeros for f(x)=3sin2x on the interval [0,2π]?
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Ответ:
Step-by-step explanation:
Trigonometric Equations
Solve
for x in [0,2π].
Dividing by 3:
Solving for 2x by using the inverse sine function:
There are two angles in the first turn of the trigonometric circle whose sine is 0:
2x=0
2x=π
Dividing by 2, we get the first two solutions:
x = 0
Since the argument of the sine is double, we look for solutions in the next turn of the circle, that is:
Again, dividing by 2:
No more solutions can be found, thus the solutions are:
Ответ:
the missing number is 4
Step-by-step explanation:
4x4=16