Which additional congruence statement could you use to prove that rqs= pqs by hl

The correct answer is last option  SR ≅ SP

Step-by-step explanation:

Points to remember

IF two right angled triangles are congruent by HL congruence, then one leg and hypotenuse of both are congruent,

To find the correct option

From the figure we get,

SQ is the common side of two triangles.

SR is the hypotenuse of ΔRQS and

SP  is the hypotenuse of ΔPQS

Therefore we need SR ≅ SP

The correct answer is last option  SR ≅ SP

y= 10/3x -18

dude above me is wrong smh.