Mathematics: Which equation has the solutions x=1 +-sqrt 5? x2 + 2x + 4 = 0 x2 – 2x + 4 = 0 x2 + 2x – 4 = 0 x2 – 2x – 4 = 0

Is that x + 2 = 4? if so, the answer should be equality....

Which equation has the solutions x=1 +-sqrt 5?

lurinha8

11.03.2022

D is correct. x^2-2x-4=0

Step-by-step explanation:

We are given the root of the equation

$x=1+\pm \sqrt{5}$

If we are given solution of the equation then find equation using formula.

If a and b are the solution of equation then equation would be (x-a)(x-b)=0

Here, $a=1+\sqrt{5} , b=1-\sqrt{5}$

Equation form would be $(x-1-\sqrt{5})(x-1+\sqrt{5})=0$

Now we simplify the above equation to get correct option.

$x^2-x+x\sqrt{5}-x+1-\sqrt{5}-x\sqrt{5}+\sqrt{5}-5=0$

x^2-2x-4=0

So, D is correct. x^2-2x-4=0

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