Which equation passes through the point (2, 3) and has a slope of -1/3

y = -x/3 + 11/3

Step-by-step explanation:

Finding equation

Given

Slope = -1/3

Point = ( 2 , 3)

using a point slope form equation

y - y1 = m( x - x1)

( 2 , 3)

x1 = 2

y1 = 3

y - 3 = -1/3( x - 2)

y - 3 = -(x - 2)/3

y - 3 =( -x + 2) / 3

y = ( -x + 2)/3 + 3

LCM = 3

y =( -x + 2 + 9)/3

y = ( -x + 11)/3

Separate to get the slope and the intercept

y = -x/3 + 11/3

The equation of the line is

y = -x/3 + 11/3

first find the length of trangel using

h^2=p^2+b^2