Which number line shows the solution set for StartAbsoluteValue 8 minus 2 p EndAbsoluteValue = 6? A number line going from negative 1 to positive 7. Points are at positive 1 and positive 7.
A number line going from negative 4 to positive 4. Points are at negative 1 and positive 1.
A number line going from negative 8 to positive 8. Points are at negative 7 and positive 7.
A number line going from negative 7 to positive 1. Points are at negative 7 and positive 1.

A number line going from negative 1 to positive 7. Points are at positive 1 and positive 7.

Step-by-step explanation:

We have the equation:

|8 - 2*p| = 6

Remember that the equation:

|f(x)| = A

with A > 0

means that:

f(x) = A

or

f(x) = -A

Then for our case, we can rewrite:

|8 - 2*p| = 6

as:

(8 - 2*p) = 6

or

(8 - 2*p) = -6

Now we can solve these two equations to find the two possible values of p.

From the first one, we get:

8 - 2*p = 6

8 - 6 = 2*p

2 = 2*p

2/2 = p = 1

so one solution is  p = 1

Now from the other equation, we can get the other solution:

(8 -2*p) = -6

8 - 2*p = -6

8 + 6 = 2*p

14 = 2*p

14/2 = p = 7

So the two solutions are p = 1 and p = 7

Then the correct option is:

"A number line going from negative 1 to positive 7. Points are at positive 1 and positive 7."

The slope of the given line is ∆y/∆x = (4-6)/(5-1) = -2/4 = -1/2. The slope of the desired (perpendicular) line is the negative reciprocal of this, -1/(-1/2) = 2.

The point-slope form of the equation for a line with slope m through point (h, k) is

... y - k = m(x - h)

For slope 2 and the given point, your equation can be

... y + 6 = 2(x + 2)