Mathematics: Which of the following are solutions to the quadratic equation? check all that apply 2x^2+14x-4=-x^2+3x

Which of the following are solutions to the quadratic

prettygirl1053473

10.03.2022

$x_1=-4\\\\x_2=\frac{1}{3}$

Step-by-step explanation:

Given the quadratic equation:

2x^2+14x-4=-x^2+3x

You can follow these steps in order to solve it:

- Make the equation equal to 0:

2x^2+14x-4+x^2-3x=0

- Now, add the like terms:

3x^2+11x-4=0

- Finally, apply the Quadratic formula ( $x=\frac{-b\±\sqrt{b^2-4ac} }{2a}$ ):

In this case we know that:

$a=3\\b=11\\c=-4$

Therefore, substituting values into the Quadratic formula and evaluating, we get:

$x=\frac{-11\±\sqrt{11^2-4(3)(-4)} }{2(3)}\\\\x_1=-4\\\\x_2=\frac{1}{3}$

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cameron12502

25.02.2021

lol

Step-by-step explanation:

Something will happen

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