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helpmeplzandty

20.08.2020

Mathematics

option (2) is correct.

$\cot x^{\circ}=\frac{adjacent}{opposite}$

Step-by-step explanation:

Given some trigonometric relations

$\sec x^{\circ}=\frac{adjacent}{opposite}$

$\cot x^{\circ}=\frac{adjacent}{opposite}$

$\cot x^{\circ}=\frac{opposite}{adjacent}$

$\sec x^{\circ}=\frac{opposite}{adjacent}$

We have to choose the correct relations

For a given right angled triangle as shown below in image.

Secant function is defined as the ratio of hypotenuse to its adjacent side.

that is $\sec x^{\circ}=\frac{hypotenuse}{adjacent}$

cotangent function is defined as the ratio of adjacent side to opposite side.

That is $\cot x^{\circ}=\frac{adjacent}{opposite}$

Thus, option (2) is correct.

Which equation is correct? . answer. sec x° = adjacent ÷ opposite. cot x° = adjacent ÷ opposite. cot

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