Write a two-column proof. Given: <2 is congruent to <5; Segment AB is congruent yo Segment DE

Prove: Segment BC is congruent to Segment EC

Write a two-column proof.

Given: <2 is congruent to <5; Segment AB is congruent yo Segment

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nidiavega2009

05.02.2020

Mathematics

Equation: $\frac{13}{15} - \frac{1}{5}$

When adding or subtracting, you have to make sure they have a common denominator

So you have to multiply $\frac{1}{5}$ by $\frac{3}{3}$

$\frac{1}{5} * \frac{3}{3} = \frac{3}{15}$

Since they both have the same denominator, you subtract

$\frac{13}{15} - \frac{3}{15} = \frac{10}{15}$

One thing to note is when subtracting, you DO NOT subtract the denominator, only the numerators

To reduce to the lowest terms, you need to find a common factor.
5 goes into 10 two times and goes into 15 three times

That leaves it with the fraction $\frac{2}{3}$

$\frac{2}{3}$

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Write a two-column proof. Given: <2 is congruent to <5; Segment AB is congruent yo Segment DE Prove: Segment BC is congruent to Segment EC