Write an equation in slope-intercept form of the line that passes through (6,-1) and (3,-7). Please help!

y = 2x – 13

Step-by-step explanation:

Use Slope formula to get the slope

(y2-y1) / (x2-x1)

(-7--1) / (3-6)

(-6)/(-3)

2

Then plug-in the value of slope and any one coordinate in Point-Slope formula:

y- y1= m(x-x1)

y - -1 = 2( x - 6)

y + 1 = 2x - 12

y = 2x - 13

  On a coordinate plane, a curved line crosses the x-axis at (negative 4, 0), (0, 0), and (4, 0)

Step-by-step explanation:

An odd function is symmetrical about the origin. It will satisfy the relation ...

  f(-x) = -f(x)

Of the given points, the set that is symmetrical about the origin is found on the 3rd graph:

  (-4, 0), (0, 0), (4, 0)