Write an equation of the line that passes through (0, 3) and (−5, 2.5).

The equation of the line will be in the form:

y=mx+c

where m is the slope (gradient) and c is the y-intercept.

To find the slope, we use:

m=y2−y1x2−x1

It doesn't matter which point we decide is (x1,y1) and which we choose as (x2,y2, since the formula will work either way.

m=0−(−5)3−(−3)=56

Now we can use the slope and the coordinates of one point - either will do - to find the y-intercept:

y=mx+c

0=56(3)+c=156+c

Rearranging:

c=0−156=−156

Over all, then, the equation of the line is:

y=56x−156

the highest is 140 there u go and can u give this a brainleits