Y=2 tan x find the vertical asymptotes

This is the concept of trigonometry, we are required to find the vertical asymptote of the function given by;
y=2tan x
For any y=tan x, vertical asymptotes occur at the point x=π/2+nπ, where is an integer given by n=0,1,2,3...
Therefore we can generate the vertical asymptotes as follows;
When x=0
y=π/2
when x=1
y=π/2+π
y=3/2π
when x=2
y=π/2+2π
y=5/2π
Therefore at the interval [0,2π]
The vertical asymptotes are:
π/2, 3/2π, 5/2π

B
5x+2y=2
2y=5x+2
y=5/2x+1