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ayleenmorar
18.03.2020 •
Mathematics
Y=f(x)=x^2+x
find the slope of the secant line joining (-3,f(-3)) and (0,f(0))
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Ответ:
-2
The problem:
y=f(x)=x^2+x
find the slope of the secant line joining (-3,f(-3)) and (0,f(0))
Step-by-step explanation:
We need to first find the values that correspond to f(-3) and f(0).
f(-3) can be found by replacing the x's in f(x)=x^2+x with (-3):
f(-3)=(-3)^2+(-3)
f(-3)=9+-3
f(-3)=6
f(0) can be found by replacing the x's in f(x)=x^2+x with (0):
f(0)=(0)^2+(0)
f(0)=0+0
f(0)=0
So we want to find the slope of the line going through the points:
(-3,6) and (0,0)
Line them up-doesn't matter which point goes on top:
(-3,6)
(0,0)
Now subtract!
-3 , 6
The rise goes over the run so the slope is 6/-3 which simplifies to -2.
Ответ:
g < 5.17
Step-by-step explanation:
Given
g + 7.25 < 12.42 ( subtract 7.25 from both sides )
g < 12.42 - 7.25
g < 5.17