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TPfishing16
13.02.2022 •
Physics
2. Apply Mathematics If the amplitude of the 6 PM wave increases to 0.6 m, how many times greater would the energy become? (Please explain solving it too please)
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Ответ:
t ’=
, v_r = 1 m/s t ’= 547.19 s
Explanation:
This is a relative velocity exercise in a dimesion, since the river and the boat are going in the same direction.
By the time the boat goes up the river
v_b - v_r = d / t
By the time the boat goes down the river
v_b + v_r = d '/ t'
let's subtract the equations
2 v_r = d ’/ t’ - d / t
d ’/ t’ = 2v_r + d / t
In the exercise they tell us
d = 1.22 +1.45 = 2.67 km= 2.67 10³ m
d ’= 1.45 km= 1.45 1.³ m
at time t = 69.1 min (60 s / 1min) = 4146 s
the speed of river is v_r
t ’=![\frac{1.45 \ 10^3}{ \frac{ 2670}{4146} \ + 2 \ v_r}](/tpl/images/1137/4869/de0ae.png)
t ’=![\frac{1450}{0.6499 + 2 v_r}](/tpl/images/1137/4869/dc608.png)
In order to complete the calculation, we must assume a river speed
v_r = 1 m / s
let's calculate
t ’=![\frac{ 1450}{ 0.6499 + 2 \ 1}](/tpl/images/1137/4869/e6ad6.png)
t ’= 547.19 s