Physics: 3–101 It is estimated that 90 percent of an iceberg’s volume is below the surface, while only 10 percent is visible above the surface. For seawater with a density of 1025 kg/m3 , estimate the density of the iceberg.

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3–101 It is estimated that 90 percent of an iceberg’s

elijah207

19.01.2022

The density of iceberg upper water and under water are 102.5 kg/m³ and 922.5 kg/m³

Explanation:

Given that,

Volume of seawater = 90 % of Volume of iceberg

Volume of visible surface = 10 %

Density of seawater = 1025 kg/m³

We need to calculate the density of the iceberg

Using equilibrium condition

$W_{I}=F_{B}$

$\rho_{I}\times V_{I}\times g= \rho_{w}\timesV_{w}\times g$

Put the value into the formula

$\rho_{I}\times V_{I}\times g=\rho_{w}\times0.9V_{I}\times g$

$\rho_{I}=1025\times0.9$

$\rho_{I}=922.5kg/m^3$

We need to calculate the density of the iceberg

Using equilibrium condition

$W_{I}=F_{B}$

$\rho_{I}\times V_{I}\times g= \rho_{w}\timesV_{w}\times g$

Put the value into the formula

$\rho_{I}\times V_{I}\times g=\rho_{w}\times0.1V_{I}\times g$

$\rho_{I}=1025\times0.1$

$\rho_{I}=102.5\ kg/m^3$

Hence, The density of iceberg upper water and under water are 102.5 kg/m³ and 922.5 kg/m³

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