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icantdomath4910
17.03.2020 •
Physics
A 0.30-kg puck, initially at rest on a frictionless horizontal surface, is struck by a 0.20-kg puck that is initially moving along the x-axis with a velocity of 5.2 m/s. After the collision, the 0.20-kg puck has a speed of 3.1 m/s at an angle of θ = 53° to the positive x-axis. (a) Determine the velocity of the 0.30-kg puck after the collision, (b) Find the fraction of kinetic energy lost in the collision.
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Ответ:
Answer :
The fraction of kinetic energy lost in the collision is 13.5%.
Explanation :
Given that,
Mass of stationary puck = 0.30 kg
Mass of moving puck = 0.20 kg
Speed = 5.2 m/s
Speed = 3.1 m/s
Angle = 53°
(a). We need to calculate the velocity
Using Conservation of momentum
Along x ,
Put the value into the formula
Along y,
Put the value into the formula
We need to calculate the velocity of the 0.30 kg puck after the collision
Using formula of velocity
Put the value into the formula
(b). We need to calculate the kinetic energy lost in the collision
Kinetic energy before collision
Kinetic energy after collision
The ratio of kinetic energy
Kinetic energy lost![=\dfrac{K.E_{f}}{K.E_{i}}-1](/tpl/images/0550/3931/655ab.png)
Put the value into the formula
Hence, The fraction of kinetic energy lost in the collision is 13.5%.
Ответ: