Physics: A 1.2 W point source emits sound waves isotropically. Assuming that the energy of the waves is conserved, find the intensity (a)1.6 m from the source and (b)2.2 m from the source.

A 1.2 W point source emits sound waves isotropically.

Ответ:

Jazzyyyy088888

19.01.2022

Physics

(a) $I = 3.7\times 10^{-2}\ W/m^{2}$

(b) $I = 1.9\times 10^{-2}\ W/m^{2}$

Explanation:

Given:

Point source $P_{b}=1.2\ W$

Distance from source Part a $L = 1.6\ m$

Distance from source Part b $L = 2.2\ m$

Solution:

Part (a)

Using intensity formula at distance L from an isotropic point.

$I = \frac{P_{b}}{4\pi(L)^{2}}$ -------------------(1)

Substitute $L = 1.6\ m$ and $P_{b}=1.2\ W$ in equation 1..

$I = \frac{1.2}{4\times 3.14(1.6)^{2}}$

$I = \frac{1.2}{32.15}$

$I = 0.037\ W/m^{2}$

$I = 3.7\times 10^{-2}\ W/m^{2}$

Part (b)

Substitute $L = 2.2\ m$ and $P_{b}=1.2\ W$ in equation 1.

$I = \frac{1.2}{4\times 3.14(2.2)^{2}}$

$I = \frac{1.2}{60.79}$

$I = 0.019\ W/m^{2}$

$I = 1.9\times 10^{-2}\ W/m^{2}$

Therefore, the intensity at distance 1.6 m from the source:

$I = 1.9\times 10^{-2}\ W/m^{2}$ .

And, the intensity at distance 2.2 m from the source:

$I = 1.9\times 10^{-2}\ W/m^{2}$ .

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Ответ:

Lakenwilliams1250

03.01.2020

Physics

B) HEAT AND GASES CONTRACTED WITHIN A NEBULA

Explanation:

1) just got it right on my flvs test and 2) This dying star exploded, sending its outer gases in a butterfly shape away from its core. It's called the Butterfly Nebula, and it lies about 3,800 light years away from Earth in the constellation Scorpius. Over time, it will become the birthplace for new stars

:-)

by -k

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A 1.2 W point source emits sound waves isotropically. Assuming that the energy of the waves is conserved, find the intensity (a)1.6 m from the source and (b)2.2 m from the source.

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