tylerjoshonti
20.07.2020 •
Physics
a ball is rolling along a ground with a velocity of 10m/s and comes to rest after 8s.what is its acceleration
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Ответ:
-1.25 m/s²
Explanation:
Use the formula a=(v-u)/t,
acceleration a = unknown
final velocity v= 0 m/s (rest)
initial velocity u = 10m/s
time t = 8s
a = (0-10)/8
a = -1.25 m/s²
Ответ: