![WhirlyWave](/avatars/48157.jpg)
WhirlyWave
23.11.2019 •
Physics
(a) calculate the number of free electrons per cubic meter for gold assuming that there are 1.5 free electrons per gold atom. the electrical conductivity of and density of gold are 4.3 x 107 (o-m)-1 and 19.32 g/cm3, respectively.
(b) now compute the electron mobility for au.
Solved
Show answers
More tips
- B Business and Finance How to Create a Business Plan? Your Ultimate Guide...
- F Family and Home Parquet or laminate, which is better?...
- L Leisure and Entertainment How to Properly Wind Fishing Line onto a Reel?...
- L Leisure and Entertainment How to Make a Paper Boat in Simple Steps...
- T Travel and tourism Maldives Adventures: What is the Best Season to Visit the Luxurious Beaches?...
- H Health and Medicine Kinesiology: What is it and How Does it Work?...
- O Other How to Choose the Best Answer to Your Question on The Grand Question ?...
- L Leisure and Entertainment History of International Women s Day: When Did the Celebration of March 8th Begin?...
- S Style and Beauty Intimate Haircut: The Reasons, Popularity, and Risks...
- A Art and Culture When Will Eurovision 2011 Take Place?...
Answers on questions: Physics
- M Mathematics What is 3 to the third power plus 6th parentheses 2 plus 3/6 parentheses equal...
- E English Before watching a video about black holes, it is important to consider how details about black holes relate to the video s purpose. think about how the video s director captured...
- M Mathematics A 1.2-kg mass is projected up a rough circular track (radius = 0.80 m) as shown. The speed of the mass at point A is 8.4 m/s, and at point B, it is 5.6 m/s. What is the change...
- M Mathematics In 2006, the population of the country was 30.4 million. this represented an increase in population of 7.6 % since 2001. what was the population of the country in 2001? round to...
Ответ:
Part A:
Part B:
Explanation:
Part A:
To calculate the number of free electrons n we use the following formula::
n=1.5N-Au
Where N-Au is number of gold atoms per cubic meter
So:
Part B:
n is calculated above which is 8.85*10^{28}m^{-3}
Charge on electron=1.602*10^{-19}
Elec- Conductivity= 4.3*10^{7}
Ответ:
Hey
The distance is easy, just add 3+9+7+9.
Answer 28m
Distance is not to be confused with displacement (the total distance from your starting point).
Wbob1314