A car accidentally rolls off cliff as it leaves the cliff it has a horizontal velocity of 13 m/s it hits the ground 60 m from the shoreline calculate the height of the cliff

The height of the cliff from which the car rolls off is 104.59 m

We'll begin by calculating the the time taken for the car to reach the ground.

Horizontal distance (s) = 60 m

Horizontal velocity (u) = 13 m/s

t = 4.62 s

Thus, the time taken for the car to reach the ground is 4.62 s

Time (t) = 4.62 s

Acceleration due to gravity (g) = 9.8 m/s²

h = ½gt²

h = ½ × 9.8 × 4.62²

Therefore, the height of the cliff is 104.59 m

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h = 104.13 m

Explanation:

Given that,

Horizontal velocity of the car, v = 13 m/s

It hits the ground 60 m from the shoreline

We need to find the height of the cliff. Let t be the time of fall. We can find it as follows :

So, the time of fall is 4.61 seconds.

Let h is the height of the cilff. Using second equation of motion to find it as follows :

So, the height of the cliff is 104.13 m.

battery's capacity determines roughly how long a battery will last at a specific voltage given a specific discharge rate. For example, if you choose a 12V, 2Ah (2000mAh) battery pack (regardless of chemistry), the battery should be able to run a 12V motor consuming 2A continuously for 1 hour. Alternatively, it can run a 12V motor consuming 1A for 2 hours, or a 12V motor consuming 0.5A for 4 hours. The rule of thumb is to divide the capacity (assuming you are running an actuator at the same voltage) by the actuator's current under normal load to get the time the motor will last.

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Explanation: