A car is traveling with a speed of 20.0 m/s along a straight horizontal road. The wheels have a radius of 0.300 m. If the car speeds up with a linear acceleration of 1.50 m/s2 for 8.00 s, find the angular displacement of each wheel during this period.

the frequency clock would be 1262.85 Hz

Explanation:

Given data;

height of building h = 25 m

from the third equation of motion;

v² = u² + 2as

Since the Alarm clock falls with an acceleration equal to the acceleration due to gravity; a = g = 9.81 m/s²

initial velocity u = 0

so we substitute our values into the kinematic equation

v² = (0)² + 2 × 9.81 × 25

v² = 490.5

v = √490.5

v = 22.1472 m/s

Now, since the alarm clock is moving both I am stationary;

my velocity will be zero.

so Frequency of the alarm clock will be;

f' = [ (v - ) / ( v + ) ] × f

we know that; speed of sound is 343 m/s, so v = 343 m/s, is 22.1472 m/s, f is 1350 Hz,  is 0 m/s

so we substitute the values into the equation

f' = [ (343 - 22.142 ) / ( 343 + 0 ) ] × 1350

f' = [ 320.858 / 343 ] × 1350

f' = 0.935446 × 1350

f' = 1262.85 Hz

Therefore, the frequency clock would be 1262.85 Hz