Physics: A charge of 4.5 × 10-5 C is placed in an electric field with a strength of 2.0 × 104 . If the charge is 0.030 m from the source of the electric field, what is the electric potential energy of the charge?

A charge of 4.5 × 10-5 C is placed in an electric - id451055678465, yourbakedpotato101

JamesLachoneus

22.01.2022

0.027 J

Explanation:

The formula of the potential energy in electrostatic (U) is

$U = q \times E \times d$

The values given in the question are

Charge : q = $4.5 \times 10^{-5} C$

Electric Field strength : E = $2.0 \times 10^{4} N/C$

Distance : d is 0.030 m

Insert in the formula , will give us

$U = 4.5 \times 10^{-5} C \times 2.0 \times 10^{4} N/C \times 0.030 m$

Further solving it

U = 0.027 J

Which is the required answer.

Thanks

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christiantorres57

17.12.2022

Uranium is the fuel most widely used by nuclear plants for nuclear fission.

Explanation:

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