misscheoneyo
24.06.2021 •
Physics
A clock battery wears out after moving 10,400 C of charge through the clock at a rate of 0.530 mA. (a) How long (in s) did the clock run? s (b) How many electrons per second flowed?
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Ответ:
Explanation:
Given that:
Charge Q = 10400 C
current I = 0.530 mA
From our previous knowledge, we know that charge Q can be expressed as:
Q = I×t
where
I = current and t = time
∴
replacing our values
10400 = (0.530×10⁻³) t
t = 10400/(0.530×10⁻³)
t = 19622641.51 seconds
However, the required flow of electrons per seconds can be calculated by using the formula:
number of electrons/second = current (I)/ charge on electron
= (0.530×10⁻³)/(1.6×10⁻¹⁹)
= 3.3125×10¹⁵ electrons
Ответ: