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liamgreene90
09.11.2020 •
Physics
A golf ball (m=26.7g) is struck a blow that makes an angle of 33.6 degrees with the horizontal. The drive lands 190m away on a flat fairway. The acceleration of gravity is 9.8 m/s^2 . If the golf club and ball are in contact for 7.13 ms, what is the average force of impact?
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Ответ:
Th average force impact is![F = 168.298 \ N](/tpl/images/0880/3545/1f205.png)
Explanation:
From the question we are told that
The mass of the golf ball is![m_g = 26.7 \ g = 0.0267 \ kg](/tpl/images/0880/3545/aea9f.png)
The angle made is![\theta = 33.6 ^o](/tpl/images/0880/3545/a8494.png)
The range of the golf ball is![R = 190 \ m](/tpl/images/0880/3545/39b72.png)
The duration of contact is![\Delta t = 7.13 \ ms = 7.13 *10^{-3} \ s](/tpl/images/0880/3545/5e0f9.png)
Generally the range of the golf ball is mathematically represented as
Here v is the velocity with which the golf club propelled it with, making v the subject
=>![v = \sqrt{\frac{190 * 9.8}{sin 2 (33.6)} }](/tpl/images/0880/3545/fc282.png)
=>![v = 44.94 \ m/s](/tpl/images/0880/3545/62851.png)
Generally the change in momentum of the golf ball is mathematically represented as
here u is the initial velocity of the ball before being stroked and the value is 0 m/s
=>![\Delta p = 1.19996 \ kg \cdot m/s](/tpl/images/0880/3545/c6f90.png)
Generally the average force of impact is mathematically represented as
=>![F = \frac{1.19996 }{7.13 *10^{-3}}](/tpl/images/0880/3545/786aa.png)
=>![F = 168.298 \ N](/tpl/images/0880/3545/1f205.png)
Ответ:
Explanation:Do you do you do you
When do you Goodwood when you cross it can go