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XTREME3336
10.03.2020 •
Physics
A hockey puck with mass 0.160 kg is at rest at the origin (x=0) on the horizontal, frictionless surface of the rink. At time t = 0 a player applies a force of 0.250 N to the puck, parallel to the x-axis; he continues to apply this force until t = 2.00s.
What is the position of the puck at t = 2.00s ?
In this case what is the speed of the puck?
If the same force is again applied at t = 5.00s , what is the position of the puck at t = 7.00s ?
In this case what is the speed of the puck?
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Ответ:
a)
, b)
, c)
, d) ![v_{f} = 6.252\,\frac{m}{s}](/tpl/images/0540/6644/1bdf0.png)
Explanation:
a) Position of the puck:
The acceleration experimented by the puck is:
As the force remains constant during its time of application, accelaration is also constant. Position at given time is the following:
b) Speed of the puck:
The speed of the puck is computed as follows:
c) The absence of external force and the fact that ground is frictionless lead to the conclusion that hockey puck moves out at constant speed from 2 s. to 5 s. Then, the initial speed is:
Likewise, the initial speed is
.
The new application of the same force means the return of a accelerated movement. Then:
d) The final speed of the puck is:
Ответ:
Resistor
Explanation: