A magnet of mass 0.20 kg is dropped from rest and falls vertically through a 35.0 cm copper tube. Eddy currents are induced, causing the copper to warm up. The speed of the magnet as it emerges from the tube is 1.50 m/s. How much heat energy is dissipated to the environment?
Solved
Show answers
More tips
- S Sport How to Pump Your Chest Muscle? Secrets of Training...
- H Horoscopes, Magic, Divination Where Did Tarot Cards Come From?...
- S Style and Beauty How to Make Your Lips Fuller? Ideas and Tips for Beautiful Lips...
- S Style and Beauty How are artificial nails removed?...
- F Family and Home How to Sew Curtain Tapes: Best Tips from Professionals...
- H Horoscopes, Magic, Divination How to Cast a Love Spell on a Guy? Guide for Guys...
- F Family and Home How to Properly Use a Water Level?...
- L Legal consultation What Documents Are Required for a Russian Passport?...
- H Health and Medicine How to Treat Styes: Causes, Symptoms, and Home Remedies...
- F Family and Home Protect Your Home or Apartment from Pesky Ants...
Answers on questions: Physics
- E English Read the passage from the opinion of the court in brown v. board of education written by justice warren what reason does warren give for making the claim that comparing tangible...
- E Engineering Hey my Curious peeps, and my Helpful Explainers❣ I have a question about a watch and I need an answer so I can fix the problem. Ok, so the watch won t turn on and I don t know...
- M Mathematics A roof of the house including its base is in the shape of right prism with a triangular base with the dimensions shown. What is the approximate surface area of this prism?...
- B Biology if the allowance method of accounting for uncollectible receivables is used, what general ledger account is debited to write off a customer s account as uncollectible?...
Ответ:
The energy lost to the environment is 0.461 J
Explanation:
Given;
mass of the magnet, m = 0.2 kg
height of fall, h = 35 cm = 0.35 m
initial speed of the magnet, u = 0
final speed of the magnet, v = 1.5 m/s
Initial energy of the magnet is given by;
E₁ = P.E₁ + K.E₁
E₁ = mgh₁ + ¹/₂mu²
E₁ = (0.2 x 9.8 x 0.35) + ¹/₂(0.2)(0)²
E₁ = 0.686 J
Final energy of the magnet as it emerges from the tube is given by;
E₂ = mgh₂ + ¹/₂mv²
E₂ = (0.2 x 9.8 x 0) + ¹/₂(0.2)(1.5)²
E₂ = 0 + 0.225 J
The energy lost to the environment is given by;
E = E₂ - E₁
E = 0.225 J - 0.686 J
E = -0.461 J (negative sign indicates lost energy to the environment)
Therefore, the energy lost to the environment is 0.461 J
Ответ:
whatever ya sayy
Explanation: