A projectile has an initial horizontal velocity of 24 m/s. What is the horizontal velocity at the max height? Explain all work.
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Ответ:
Explanation: Let the initial velocity be x₀
According to the question, x₀cosθ = 5m/s
And x₀sinθ = 6.5m/s
Angle of projection = ?
Let the angle of projection be θ
So,
x₀sinθ / x₀cosθ =
We know,
sinθ / cosθ = tanθ
Thus,
tanθ =
tanθ = 1.3
θ = tan⁻¹ (1.3)
θ = 52.4⁰
Ответ: