Physics: Acompletely ionized beryllium atom (net charge = +4e) is accelerated through a potential difference of 6.0 v. what is the increase in kinetic energy of the atom?

Acompletely ionized beryllium atom (net charge

Ответ:

evelyng58

15.03.2022

For the principle of conservation of energy, the increase in kinetic energy of the atom is equal to the energy lost when moving through the potential difference:
$\Delta K=\Delta U=q \Delta V$
where q is the charge of the Beryllium atom:
$q=4 e=4 \cdot (1.6 \cdot 10^{-19}C)=6.4 \cdot 10^{-19}C$
and $\Delta V=6.0 V$ . Therefore, the increase in kinetic energy is
$\Delta K = (6.4 \cdot 10^{-19}C)(6.0 V)=3.8\cdot 10^{-18} J$

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Ответ:

ericgideon

05.08.2022

Physics

I don’t speak your languag ;-;

Step-by-step explanation:

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Acompletely ionized beryllium atom (net charge = +4e) is accelerated through a potential difference of 6.0 v. what is the increase in kinetic energy of the atom?

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