Physics: After a surface interval my pressure group is D. I want to do a repetitive dive to 38 feet for 32 minutes. What will be my new pressure group when I reach the surface?

The speed of a point on the rim is equal to 2.45 meters per seconds.Given the following data:Mass of disk = 100 gDiameter of disk = 8 cmKinetic energy = 0.15 JoulesConversion:Diameter of disk = 8 cm to m = = 0.08 metersMass of disk = 100 g to kg = = 0.1 kgRadius = = 0.04 mTo find the speed of a point on the rim:First of all, we would determine the moment of inertia (I) of the disk.Moment of inertia, I = 0.00008 Next, we would solve for angular velocity from the rotational kinetic energy of the disk:Angular...

After a surface interval my pressure group is D.

Ответ:

skylarschumacher7

19.01.2022

Physics

Explanation: Finding the new pressure group would involve looking into the Repetitive Dive Table, where we will be interested in finding the Residual Nitrogen time(RNT). The Residual Nitrogen Time value is the intersection of the pressure group D at 12m which according to the table is 26 min. This value '26' will be added to the next dive which is ; 32 min + 26min =58.

The intersection of value '58' at 12m is located in the table to find the next value of the pressure group. Which according to the table is N.

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Ответ:

denisturcios18

10.11.2021

Physics

The speed of a point on the rim is equal to 2.45 meters per seconds.

Given the following data:

Mass of disk = 100 gDiameter of disk = 8 cmKinetic energy = 0.15 Joules

Conversion:

Diameter of disk = 8 cm to m = $\frac{8}{100}$ = 0.08 meters

Mass of disk = 100 g to kg = $\frac{100}{1000}$ = 0.1 kg

Radius = $\frac{diameter}{2} = \frac{0.08}{2}$ = 0.04 m

To find the speed of a point on the rim:

First of all, we would determine the moment of inertia (I) of the disk.

$I = \frac{1}{2} mr^2\\\\I = \frac{1}{2} \times 0.1 \times 0.04^2\\\\I = 0.05 \times 0.0016$

Moment of inertia, I = 0.00008 kgm^2

Next, we would solve for angular velocity from the rotational kinetic energy of the disk:

$E_R = \frac{1}{2} Iw^2\\\\0.15 = \frac{1}{2} \times 0.00008 \times w^2\\\\0.3 = 0.00008w^2\\\\w^2 = \frac{0.3}{0.00008} \\\\w^2 = 3750\\\\w = \sqrt{3750}$

Angular velocity, w = 61.24 rad/s

Now, we can find the speed:

$Speed = rw\\\\Speed = 0.04 \times 61.24$

Speed = 2.45 m/s

After a surface interval my pressure group is D. I want to do a repetitive dive to 38 feet for 32 minutes. What will be my new pressure group when I reach the surface?

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