Aman pushes his child in a grocery cart. the total mass of the cart and child is 30.0 kg. if the force of friction on the cart is 15.0 n, how hard does the man have to push so that the cart accelerates at 1.50 m/s/s?

Newton's second law states that the resultant of the forces applied to an object is equal to the product between the object's mass and its acceleration:

where in our problem, m is the mass the (child+cart) and a is the acceleration of the system.

We are only concerned about what it happens on the horizontal axis, so there are two forces acting on the cart+child system: the force F of the man pushing it, and the frictional force  acting in the opposite direction. So Newton's second law can be rewritten as

or


since the frictional force is 15 N and we want to achieve an acceleration of , we can substitute these values to find what is the force the man needs:

Fc₂ = 4.675 N

Explanation:

r₁ = 12 cm = 0.12 m

Fc= 1.7 N

Fc = mV²/r = m w² r   ( ∴  V= r w )

Fc = m w² r   (1)

As angular speed (w) and mass are constant.

let    m * w² = k   (2)

Put equation (2) in equation (1).

⇒  Fc = m w² r = k * r         ( ∴ m w² = k)

⇒  Fc =k * r     ( 3)

⇒  Fc₁ =k * r₁ = 1.7 N

⇒ k = 1.7/ r  = 1.7 / 0.12  N    ( as r₁=0.12 m )

⇒ k = 14.17

Centripetal force hen the rod is fixed at 33 cm from the axis:

From equation ( 3 )

Fc₂ =  k * r₂

Fc₂ = 14.17 * 0.33 N    ( ∴ r₂ = 0.33 m)

Fc₂ = 4.675 N