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charati5408
28.07.2019 •
Physics
Aman weighing 680 n and a woman weighing 470 n have the same momentum. what is the ratio of the man's kinetic energy km to that of the woman kw? view available hint(s)
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Ответ:
47/68
Explanation:
They have the same momentum, so:
(680/g) v₁ = (470/g) v₂
680 v₁ = 470 v₂
The man's kinetic energy is:
KE = ½ mv²
KE₁ = ½ (680/g) v₁²
The woman's kinetic energy is:
KE = ½ mv²
KE₂ = ½ (470/g) v₂²
The ratio is:
KE₁ / KE₂ = [½ (680/g) v₁²] / [½ (470/g) v₂²]
KE₁ / KE₂ = (680 v₁²) / (470 v₂²)
KE₁ / KE₂ = (680² v₁²) / (680 × 470 v₂²)
KE₁ / KE₂ = (680 v₁)² / (680 × 470 v₂²)
KE₁ / KE₂ = (470 v₂)² / (680 × 470 v₂²)
KE₁ / KE₂ = 470 / 680
KE₁ / KE₂ = 47 / 68
Ответ: