Askydiver of mass 80.0 kg jumps from a slow-moving aircraft and reaches a terminal speed of 50.0 m/s. (a) what is her acceleration when her speed is 30.0 m/s? what is the drag force on the skydiver when her speed is

6.3 m/s²

Explanation:

m = mass of the skydiver = 80.0 kg

k = constant

v = speed at any time

a = acceleration

W = weight = mg = 80 x 9.8 = 784 N

Force equation for the motion of skydiver is given as

W - k v² = ma

at v = 50 m/s , a = 0

784 - k (50)² = (80) (0)

k = 0.3136

At v = 30 m/s, equation can be written as

W - k v² = ma

784 - (0.3136) (30)² = 80 a  

a = 6.3 m/s²

Explanation:

Momentum is given by .

Let be the initial momentum of the object:

If we doubled the mass, the new mass would be , and if we halved the velocity, the new velocity would be .

Therefore, the final momentum would be:

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