Physics: Asubmarine reaches the depth of 105 m (densi-ty of sea water = 1030 kg/m).calculate the absolute pressure that the subma-rine need to be able to withstand.

Asubmarine reaches the depth of 105 m (densi-ty

Ответ:

Aycla123

08.01.2022

Physics

The pressure the the submarine need to able to withstand is

P=1.161195 Mpa

P=1.161195 $x10^{6}$ pa

Explanation:

$Pressure= (Density_{object} *Gravity*Depth_{object} )+Pressure_{atmosphere}\\Pressure_{atmosphere}=101325 pa \\\\P=(1030 \frac{kg}{m^{3}}*9.8\frac{m}{s^{2} }*105m)+ 101325 pa\\P=(1059870 \frac{kg*m^{2} }{m^{3}*s^{2}})+101325 pa\\P=(1059870 \frac{N}{m^{2}}+101325 pa\\ P=1059870 pa +101325 pa=1161195pa\\P=1.161x10^{6}pa\\ P=1.161Mpa$

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Ответ:

Bashirar19

27.08.2021

Physics

With the French and Indian War over, many colonists saw no need for soldiers to be stationed in the colonies. Britain also needed money to pay for its war debts. I hope it helps!

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Asubmarine reaches the depth of 105 m (densi-
ty of sea water = 1030 kg/m

).
calculate the absolute pressure that the subma-
rine need to be able to withstand.

Ответ:

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