At a pressure 49 kpa, the gas in a cylinder has a volume of 11 liters. assuming temperature remains the same, if the volume of the gas is decreased to 4 liters, what is the new pressure?
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Ответ:
1 / p = V / (p0 × V0)
p = (p0 × V0) / V = (49kPa × 11L) / 4L = 134.75kPa
Ответ: