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kelseiroll9759
15.04.2020 •
Physics
At noon on a clear day, sunlight reaches the earth's surface at Madison, Wisconsin, with an average intensity of approximately 5.00 5.00 kJ·s−1·m−2. If the sunlight consists of photons with an average wavelength of 510.0 nm, how many photons strike a 7.00 7.00 cm2 area per second?
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Ответ:
7.175*10^18
Explanation:
Energy of a wave:
E = nhc/λ, where
E = energy of the wave
n = no of photons
h = Planck's Constant
c = speed of light
λ = wavelength of the wave
4000 = (n * 6.63*10^-34 * 3*10^8) / (510*10^-9)
4000 = 1.989*10^-25 * n / 510*10^-9
4000 = 3.9*10^-19 * n
n = 1.025*10^22 photons per second per meter²
7.0 cm² = 7.0 / 10,000 m²
= 7 x 10⁻⁴
Photons per second = 1.025*10^22 * 7 x 10⁻⁴
= 7.175*10^18 photons per second
Ответ:
D and C
Explanation:
Moisture is removed and ozone absorbs uv rays