Athin rod has a length of 0.25 m and rotates in a circle on a frictionless tabletop. the axis is perpendicular to the length of the rod at one of its ends. the rod has an angular velocity of 0.29 rad/s and a moment of inertia of 1.30 10-3 kg · m2. a bug standing on the axis decides to crawl out to the other end of the rod. when the bug (mass = 4.2 10-3 kg) gets where it's going, what is the angular velocity of the rod?

Given:
thin rod
→ length of 0.25 m
→  angular velocity of 0.29 rad/s
→ moment of inertia of 1.30 x 10⁻³ kg · m2

bug : mass = 4.2 x 10⁻³ kg

When the bug arrives at the end of the rod, it adds up to the initial inertia.

new inertia = 1.3 x 10⁻³ kg*m² + [4.2 x 10⁻³ kg*(0.25m)²] 
new inertia = 1.5626 x 10⁻³

initial inertia * angular velocity = new inertia * angular velocity
1.30 x 10⁻³ kg*m²   *  0.29 rad/s = 1.5626 x 10⁻³ * angular velocity
(1.30 x 10⁻³ kg*m²  *  0.29 rad/s) / 1.5626 x 10⁻³  = angular velocity 
0.24 rad/s = angular velocity

The angular velocity of the rod after the bug reach its end is 0.24 rad/s

-3=k

Step-by-step explanation:

First you have to remove the numbers that are in the side of the variable,by changing them with the opposite from both sides

26-5=5-7k-5

21=-7k

now you have to divide both sides by the number the variable is next to

21/-7=-7k/-7

-3=k