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toricepeda82
15.09.2019 •
Physics
Atruck is traveling on a straight stretch of of highway at 120 km/h. the driver spots a police car ahead. if the truck slows with an average acceleration of -4.0 m/s2 how much time does it take to reduce its speed to the legal limit of 96 km/h?
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Ответ:
It takes 1.67 seconds to reduce its speed to the legal limit
Explanation:
The main point in this problem is the difference between the units of
the speeds and acceleration
The unit of the speeds is km/hour
The unit of the acceleration is m/sec²
So we must to change the units of the speeds from km/hour to
meter/second
1 km = 1000 m
1 hour = 60 × 60 = 3600 seconds
Then 120 km/hr =
m/s
96 km/hr =
m/s
To find the time of deceleration (to reduced the speed) we will use:
v = u + at. where u is the initial velocity, v is the final velocity, a is the
acceleration and t is the time
v = 26.67 m/s , u = 33.33 m/s , a = - 4 m/s²
Substitute these values in the rule
26.67 = 33.33 + (- 4)t
Subtract 33.33 from both sides
- 6.66 = - 4t
Divide both sides by - 4
t = 1.67 seconds
It takes 1.67 seconds to reduce its speed to the legal limit
Ответ: