Physics: Both car a and car b leave school at the same time, traveling in the same direction. car a travels at a constant speed of 75 km/h, while car b travels at a constant speed of 91 km/h. how far is car a from school 1.7 h later? answer in units of km.

W = 29.06 KJExplanation:The work done while stretching the leash can be calculated by the following formula:whee,W = Work Done = ?Fₓ = Forcing Function = (-5.7 N/m)x - (78 N/m²)x²a = starting point of x = 0 mb = end point of x = 22 mTherefore,W = 29.06 KJ...

Both car a and car b leave school at the same time,

Ответ:

jothianddeepi

14.05.2021

Physics

W = 29.06 KJ

Explanation:

The work done while stretching the leash can be calculated by the following formula:

$W = \int\limits^b_a {F_{x}} \, dx \\$

whee,

W = Work Done = ?

Fₓ = Forcing Function = (-5.7 N/m)x - (78 N/m²)x²

a = starting point of x = 0 m

b = end point of x = 22 m

Therefore,

$W = \int\limits^{22\ m}_{0\ m} {(-(5.7\ N/m)x - (7.8\ N/m^{2})x^{2}}) \, dx \\Integrating\ we\ get:\\W = -\frac{(5.7\ N/m)x^{2}}{2} - \frac{(7.8\ N/m^{2})x^{3}}{3}\\Applying\ limits:\\W = -\frac{(5.7\ N/m)(22\ m)^{2}}{2} - \frac{(7.8\ N/m^{2})(22\ m)^{3}}{3} - 0\\W = - 1379.4\ J - 27684.8\ J\\W = 29064.2\ J$

W = 29.06 KJ

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Both car a and car b leave school at the same time, traveling in the same direction. car a travels at a constant speed of 75 km/h, while car b travels at a constant speed of 91 km/h. how far is car a from school 1.7 h later? answer in units of km.

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