Physics: given a circuit powered at 12V with R1, R2, R3 respectively of 10,20,30 Ohm, determine R4 in such a way that the Wheatstone bridge is in equilibrium and then calculate voltages and currents as for reference exercise.

0.00321 NmExplanation: = Final angular velocity = 3.5 rad/s = Initial angular velocity = 0 = Angular acceleration = Angle of rotation = 2 revEquation of rotational motionMoment of inertia is given byTorque is given byThe torque required is 0.00321 Nm...

given a circuit powered at 12V with R1, R2, R3 respectively

Ответ:

tubbs45

10.02.2022

Physics

The balanced condition for Wheat stones bridge is

as is obvious from the given values.

No, current flows through galvanometer is zero.

Now, P and R are in series, so

Resistance,R

=P+R

=10+15=25Ω

Similarly, Q and S are in series, so

Resistance R

=R+S

=20+30=50Ω

Net resistance of the network as R

and R

are in parallel

6×3

=0.36 A.

Explanation:

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Ответ:

deena7

18.12.2020

Physics

0.00321 Nm

Explanation:

$\omega_f$ = Final angular velocity = 3.5 rad/s

$\omega_i$ = Initial angular velocity = 0

$\alpha$ = Angular acceleration

$\theta$ = Angle of rotation = 2 rev

Equation of rotational motion

$\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \alpha=\frac{\omega_f^2-\omega_i^2}{2\theta}\\\Rightarrow \alpha=\frac{3.5^2-0^2}{2\times 2\pi \times 1.8}\\\Rightarrow \alpha=0.54156\ rad/s^2$

Moment of inertia is given by

$I=mr^2\\\Rightarrow I=0.25\times 0.154^2\\\Rightarrow I=0.005929\ kgm^2$

Torque is given by

$\tau=I\alpha\\\Rightarrow \tau=0.005929\times 0.54156\\\Rightarrow \tau=0.00321\ Nm$

The torque required is 0.00321 Nm

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given a circuit powered at 12V with R1, R2, R3 respectively of 10,20,30 Ohm, determine R4 in such a way that the Wheatstone bridge is in equilibrium and then calculate voltages and currents as for reference exercise.

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