Hi, i am having issues with this physics question. i find it quite complicated to solve and i don't even have the answer to this question. could someone explain me this question and give me the answer? !

200 m

Explanation:

Both Jerry and Tom start at the end of the pipe where the cheese is.  Jerry then runs into the pipe at 20 m/s while Tom chases him at 10 m/s.  When Jerry reaches the other end of the pipe, where Tom's cousin is, he turns around.  Eventually, he reaches Tom again, so he turns around again.  This continues until both Tom and Jerry reach the end of the pipe where Tom's cousin is.

We need to find the distance traveled by Jerry.  We already know Jerry's speed, so we just need to find the time.  We can do that using Tom's speed and the length of the pipe.

x = vt

100 m = (10 m/s) t

t = 10 s

So both Tom and Jerry run for 10 seconds.  Since Jerry runs at a speed of 20 m/s, the distance he travels is:

x = vt

x = (20 m/s) (10 s)

x = 200 m

Jerry runs a distance of 200 meters.

It will take 0.01 s or 10 ms

Solution:

As per the question:

Length of the packet, L = 1,000 bytes =

Distance, d = 2500 km =

Speed of propagation, s =

Transmission rate, R = 2 Mbps

Now,

Propagation time, t can be calculated as:

t = 10 ms