I need help on this question.........

B

Explanation:

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Refer to the diagram shown below.

The river flow south at a velocity of 1.4 m/s.
The motorboat moves east with velocity of 4.7 /s

The velocity of the motorboat relative to the earth, v, is the vector sum of the two velocities. Its magnitude, by the Pythagorean theorem, is
v = √(4.4² + 1.4²)
   = 4.904 m/s

Its direction south of east, is at an angle, θ, given by
tan θ = 1.4/4.7 = 0.298
      θ = tan⁻¹ 0.298 = 16.6°

The velocity of the motorboat is 4.9 m/s, at 16.6° south of east.