In 1996, NASA performed an experiment called the Tethered Satellite experiment. In this experiment a 2.84 x 104-m length of wire was let out by the space shuttle Atlantis to generate a motional emf. The shuttle had an orbital speed of 5.01 x 103 m/s, and the magnitude of the earth's magnetic field at the location of the wire was 5.16 x 10-5 T. If the wire had moved perpendicular to the earth's magnetic field, what would have been the motional emf generated between the ends of the wire?
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Ответ:
The motional emf generated between the ends of the wire is
7341 V
Explanation:
Given :
Length of satellite
m
Magnetic field
T
Speed of shuttle![v = 5.01 \times 10^{3} \frac{m}{s}](/tpl/images/0561/7151/d7e7f.png)
The emf generated between the ends of the wire is given by,
Induced emf =![Blv\sin \theta](/tpl/images/0561/7151/0a804.png)
Where![\sin 90 = 1](/tpl/images/0561/7151/18a97.png)
emf =![5.16 \times 10^{-5} \times 5.01 \times 10^{3} \times 2.84 \times 10^{4}](/tpl/images/0561/7151/5372c.png)
emf ≅
V
Therefore, the motional emf generated between the ends of the wire is
7341 V
Ответ:
The initial speed of the bolt is not 58.86 m/s.
Let a be the acceleration of the rocket.
During the 4 sec lift off, the rocket has reached a height of
h = (1/2)*a*t^2
with t=4,
h = (1/2)*a^16
h = 8*a
Its velocity at 4 sec is
v = t*a
v = 4*a
The initial velocity of the bolt is thus 4*a.
During the 6 sec fall, the bolt has the initial velocity V0=-4*a and it drops a total height of h=8*a. From the equation of motion,
h = (1/2)*g*t^2 + V0*t
Substituting h0=8*a, t=6 and V0=-4*a into it,
8*a = (1/2)*g*36 - 4*a*6
Solving for a
a = 5.52 m/s^2