Lonnie pitches a baseball of mass 0.20 kg. the ball arrives at home plate with a speed of 40 m/s and is batted straight back to lonnie with a return speed of 60 m/s. if the bat is in contact with the ball for 0.050 s what is the impulse experienced by the ball? a. 360 n.s b. 20 n.s c. 400 n.s d. 9.0 n.s
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Ответ:
B) 20N.s is the correct answer
Explanation:
The formula for the impulse is given as:
Impulse = change in momentum
Impulse = mass × change in speed
Impulse = m × ΔV
Given:
initial speed = 40m/s
Final speed = -60 m/s (Since the the ball will now move in the opposite direction after hitting the bat, the speed is negative)
mass = 0.20 kg
Thus, we have
Impulse = 0.20 × (40m/s - (-60)m/s)
Impulse = 0.20 × 100 = 20 kg-m/s or 20 N.s
Ответ: