Se lanza un cuerpo de 25 kg sobre un plano horizontal, con una velocidad de 20 m/s. Si el coeficiente de rozamiento es de 0,4 calcula el valor de la fuerza de rozamiento y el espacio que recorrerá el cuerpo hasta pararse
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Ответ:
1. 98 N
2. 51.0 m
Explanation:
masa 25 kg
velocidad 20 m/s
coeficiente de rozamiento .4
Fuerza de rozamiento:
mu * N, where mu = coeficiente de rozamiento, N = fuerza normal
Calcula N:
F = ma = 25 * -9.8 = -245 N
F rozamiento = mu * N = .4 * -245 = -98 N
Espacio que recorrerá:
F rozamiento = ma
-98 = 25a
a = -3.92 de-aceleración de la fuerza
vf = 0 m/s
vf = at + vi
0 = -3.92t + 20
t = 5.10 seg
x = 1/2 at^2 + vi*t
= 1/2 * -3.92 * 5.10^2 + 20*5.10
= 51.0 m
Ответ:
8 Ω: ⇒ 7.5 A
10 Ω: ⇒ 6.0 A
12 Ω: ⇒ 5.0 A